Make 24 with 8,8,3,3

Make 24 with 8,8,3,3

24 by the use of 8,8,3,3:-

[(3! * 8) - (8 * 3)]

= (6 * 8) - 24

= 48 - 24

= 24.......

Simple coded math made complex

Supply the digits from 0-9 to decode the given problem.

seven+seven+seven+seven+seven+seven+seve

n+seven+seven+seven+
three+three+three+three+nine+nine=hundred

10 times seven,

4 times three
2 times nine


...SEVEN
...SEVEN
...SEVEN
...SEVEN
...SEVEN
...SEVEN
...SEVEN
...SEVEN
...SEVEN
...SEVEN
..THREE
..THREE
..THREE
..THREE
...NINE
...NINE

............

HUNDRED

..87375
..87375
..87375
..87375
..87375
..87375
..87375
..87375
..87375
..87375
..41977
..41977
..41977
..41977
...5657
...5657
----------
1052972

Here
H=1,
D=2
V=3
T=4
N=5
I=6
E=7
S=8
R=9
U=0


Pls check if correct.
I=6

Cricket Puzzle

Some boys are playing cricket. Wasim is at the striker' s end of the pitch and
Rachit is at the non-striker' s end. Wasim hits the ball far into the outfield and the
batsmen start running. Each of them runs at a constant speed, though their speeds are
not necessarily equal. They first cross each other at a distance of 9 ft from the striker' s
end while running the first run. They immediately turn back for the second run and cross each other at a distance of 3 ft from the non-striker' s end while running for the
second run. After this, they turn back for the third run and so on. What is the total
distance (In feet) Rachit has run when they cross each other for the third time?

Let Wasim and Rachit are running at a speed of 'S1','S2' repectively.
Assume that the length of the pitch is 'x'

When they crossed each other for 1st time,
Wasim covered a distance of 9 feet and
Rachit covered (x-9) feet.
Since both are running at their own individual constant speeds, the distance covered by them is proportional to their speed

S2/S1 = (x-9)/9 --- (1)

When they crossed each other for 2nd time,
Wasim covered a distance of (x+3) feet and
Rachit covered (2x-3) feet.

S2/S1 = (2x-3)/(x+3) --- (2)

Solving both the equation we get x = 24 feet.

From the explanation given in the above post I am taking 'y' as the distance from the non striker end where Wasim and Rachit crossed fo the 3 rd time.
Since wasim is still trying to complete his 2nd run he covered a distance of (x+y) feet
Rachit already completed his 2nd run and going to complete his 3rd run he covered a distace of (2x+y) feet

S2/S1 = (2x+y)/(x+y) ..... (3)

Solving the equations and substituting the value of 'x' we get 60 feet as the answer.

Insurance company

Insurance company

A man would like to take a new health insurance. An officer taking care of these matters says to the man: "Please tell me how many children you have." The man answers: "I have three of them." The officer: "What are the ages of your children?". The man answers: "The product of the ages is equal to 36." The officer replies: "This is not enough information Sir!". "Sorry that I was a little bit unclear, but the sum of the ages is equal to the number of shops in front of your office," says the man. The officer: "This still isn't enough information Sir!". The man replies: "My oldest child loves chocolate." The officer: "Thanks for your cooperation, I now know the ages."
Are you as smart as the officer? Then give the ages of the children.




The product of the ages is 36. Using this one can make the following combination of ages:

1,36, 1 sum = 38
1,18, 2 sum = 22
1,12, 3 sum = 16
1, 9, 4 sum = 14
1, 6, 6 sum = 13
2, 9, 2 sum = 13
2, 6, 3 sum = 11
3, 3, 4 sum = 10

After the man had said that the product of the ages is equal to 36, the officer didn't have enough information. Then he was told that the sum is equal to number of shops in front of the office. He replied by saying that this still isn't enough information. So the sum of the ages should be 13, because otherwise he would have known the ages immediately. The last statement is that that the oldest child loves chocolate. So there is an oldest child. Hence the officer concludes that the ages of the children are 2, 2 and 9 years.

Fake coins

Fake coins

Suppose you have five bags filled with the same type of coins and a weigthing machine. One of this bags is completely filled with fake coins, the other bags contain only real ones. A real coin weights 10 gram and a fake one 11 gram.
What is the minimal number of times you need to use the weighting machine in order to find the bag with the fake coins?




Take 1 coin from the first bag, 2 from the second, 3 out of the third, 4 from the fourth and 5 coins from the fifth bag. Now weigh all these coins togeheter at once. If the fake coins are in the first bag, the result of the weighting will be 11 + 20 + 30 + 40 + 50 = 151 gram. Likewise, if the fake coins are in respectively the second, the third, the fourth and the fifth bag, the result of the weighting will be 152, 153, 154 and 155 gram. Hence in this way it is possible to find the bag with the fake coins with weighting only once.

Whats the next number?

Whats the next number?

17, 29, 101, 1541, _____ ?



(17*2)-5*1=29
(29*4)-5*3=101
(101*16)-15*5=1541


(1541*256)-75*5=393971

instead of 75*5 it will b 75*7...final ans right

the logic is 5*1 gets carry forward in the next line and now 5*3=15...nw 15*5=75....den 75*7=525...den 525*9=4725


The 6th term will be ====25819278731

Children.

A number of children are standing in a circle. They are evenly spaced and the 4th child is directly opposite the 18th child. How many children are there altogether?


28

Banana Camel Puzzle!!

A banana plantation is located next to a desert. The plantation owner has 3000 bananas that he wants to transport to the market by camel, across a 1000 kilometre stretch of desert. The owner has only one camel, which carries a maximum of 1000 bananas at any moment in time, and eats one banana every kilometre it travels. What is the largest number of bananas that can be delivered at the market?



533.

Straight line sum

Correct the equation above by inserting one straight line.

Answer

TV channel code

TV channel code

Some TV channels and their codes are given below
TV channel Code
ZEE CINEMA 972
STAR PLUS 4779
DD NATIONAL 292
Then code for SAHARA ONE is
Options:
1) 3502
2) 393
3) 3052
4) 1436
5) 786
6) 2330
7) 2033
8) 519
9) 617
10) 324

TV channel ..... Code
ZEE CINEMA .... 972
STAR PLUS ....... 4779
DD NATIONAL ....... 292

I tried by taking sum of letters nos according to English alphabet.

ZEE CINEMA ... Sum of all numbers ......81..........which is equal to 9+72 from 972
STAR PLUS ....... 4779....... Sum of all numbers ...126 which is equal to 47+79 of 4779
DD NATIONAL ....... 292 ...... same logic

To get 9 from 3 letters of Zee Cinema and 72 from balance 6 letters , I rearranged them in alphabetical order and grouped in 3 and 6 letters.

Like ZEE CINEMA beame ACE EEIMNZ

after taking the letters in increasing order
Sum of position of letters according to English alphabet is
(1+3+5) = 9 and (5+5+9+13+14+26) = 72
which is given code.
Similarly checked for others.

SAHARA ONE ...sum of numbers of lettrs ....82

SAHARA ONE became AAAEHN ORS with same logic.

Now sum of position of letters according to English alphabet is
1+1+1+5+8+14 = 30
and 15+18+19 = 52

so code 3052.

How can it be?

How can it be?

A doctor and a nurse have a baby boy. But the boy's father is not the doctor and the mother is not the nurse. How can it be?

Because..

It is a Female Doctor and a Male Nurse.

Logic Puzzle!!

One Teacher has 9 students

He gave them

1- 20 Balls

2- 30 Balls

3- 40 Balls

4- 50 Balls

5-60 Balls

6-70 Balls

7-80 Balls

8-90 Balls

9 - 100 Balls

He told to his students that the selling price of the ball remain same.

and the revenue should also be remain same.

means revenue from 20 Balls

and 100 Balls should remain same???

with the same selling price???

Solution!!!

First day SP will be 11 Balls for 1 rs.

20-11 = 9 Balls Left, Rev= 1

30-22 = 8 BL,r= 2

40-33= 7 BL, r= 3

50-44 = 6 BL, r= 4

60-55 = 5 r=5

70-66= 4 r=6

80-77= 3 r= 7

90-88 = 2 r= 8

100-99 = 1 r=9

Second day SP will be 1rs for 1 balls.

Rev= 1+9= 10

2+8= 10

3+7= 10

4+6= 10

5+5= 10

6+4= 10

7+3= 10

8+2= 10

9+1= 10

Sp Sp is same and rev is same.....

Lost your way

You're travelling to some village. At some point there is a fork in the road. You could go two ways but only one of them leads to the village. Lucky for you there are two men standing next to the fork. But unfortunately one of them always lies and one always speaks the truth and you do not know who is who. Since the men do not really like to help you, you are allowed to ask one of them only one question. Which question should you ask?


Ask one of the men, "if I would ask the man standing next to you: which is the road to the village?, what would he answer?"
If you ask this to the liar, he will point you in the wrong way.
If you ask this to the one who speaks the truth, he will also point you in the wrong way.

So after asking the question, take the other way. This will bring you in the village.

Find the way to freedom

A peasant is convicted in China. He gets the death penalty. The judge allows him to say a last sentence in order to determine the way the penalty will be carried out. If the peasant lies, he will be hanged, if he speaks the truth he will be beheaded. The peasant speaks a last sentence and to everybody surprise some minutes later he is set free because the judge cannot determine his penalty.

What did the peasant said?


The peasant said: "I shall be hanged!"

If the peasant was lying, he would be hanged. But that's what the peasant was saying. So he speaks the truth. But if he speaks the truth, he would be beheaded, so then he was not speaking the truth. So it is impossible for the judge to determine wether the peasant speaks the truth or not. So therefore the judge cannot determine the penalty and sets the peasant free.

Divisible from 1 to 9

Find a number consisting of 9 digits in which each of the digits from 1 to 9 appears only once. This number should satisfy the following requirements:
a. The number should be divisible by 9.
b. If the most right digit is removed, the remaining number should be divisible by 8.
c. If then again the most right digit is removed, the remaining number should be divisible by 7.
d. etc. until the last remaining number of one digit which should be divisible by 1.

The number is 381654729 because
381654729 / 9 = 42406081
38165472 / 8 = 477068
3816547 / 7 = 545221
381654 / 6 = 63609
38165 / 5 = 7633
3816 / 4 = 954
381 / 3 = 127
38 / 2 = 19
3 / 1 = 3


How do you find this number?

Let's call the digits of the number G we are looking for respectively a1 till a9. So G = a1a2a3a4a5a6a7a8a9. For convenience we define G(1) = a1, G(2) = a1a2, ..., G(9) = G.

Step 1.
It is immediately clear that a5 = 5, because if there are only 5 digits left then we have G(5) which should be divisible by 5. That is only possible if a5 = 5.
Step 2.
An odd number is not divisible by an even number.
Hence a2,a4,a6 and a8 should be even, because they were not, G(2) would not be divisible by 2, G(4) not by 4, etc.
So a2,a4,a6,a8 = 2,4,6 or 8.

Step 3.
Because there are 4 even numbers in G, which are used for a2,a4,a6 and a8, the digits a1,a3,a5,a7 and a9 are necessarily odd.
Using step 1, a1,a3,a7,a9 = 1, 3, 7 or 9.

Step 4.
G(6) has to be divisible by 6. A number is divisible by six, it should be even and the sum of its digits should be divisible by 3. Since a6 is even, G(6) is even as well. G(6) is divisible by 3 if a1+a2+a3+a4+a5+a6 is divisible by 3. Because G(3) is divisible by 3 by construction, a1+a2+a3 is divisible by 3. So G(6) is divisible by 3 3 if a4+a5+a6 is divisible by 3 as well. From step 1 it follows that a5 = 5. So a4a5a6 is either 258, 456, 654 or 852. But from these four numbers, only 258 and 654 are divisible by 3.
Hence: a4a5a6 = 258 or 654.

Step 5.
Because 200, 400, 600, 800 and 1000 are divisible by 8, a number in which the second to last digit is even, is divisible by 8 if the number formed using the last two digits is divisible by 8. For example, 234216 is divisible by 8 because the twee second to last digit (2) is even, and because 16 is divisible by 8.
a6 is even. So G(8) is divisible by 8 if a7a8 is divisible by 8. a7 is an odd number, a8 even.
So the only possibilities are: a7a8 = 16, 32, 72, 96.

Step 6.
From Step 4 it follows that either a4 = 2 or 6.
If a4 = 2, then a6 = 8 (Stap 4), a8 = 6 (Step 5). Using Step 5 it follows that a7 = 1 or 9.
If a4 = 6, then a6 = 4 (Stap 4), a8 = 2 (Step 5). Using Step 5 it follows that a7 = 3 of 7.
As a consequence, a2 is either 4 or 8 .

Step 7.
A number is divisible by 3 if the sum of its digits is divisible by 3. Because G(3) has to be divisible by 3, and using that a2 = 4 or 8 (Step 6), the following possibilities arise: G(3) = 147, 183, 189, 381, 387, 741, 783, 789, 981, 987.

Step 8.
A number is divisible by 9 if the sum of its digits is divisible by 9. For the number G we are looking for this is always the case because 1+2+3+4+5+6+7+8+9 = 45, which is divisible by 9.
Using the results of the previous steps, we find the following possibilities for G. 147258963
183654729
189654327
189654723
381654729
741258963
789654321
981654327
981654723
987654321

We did not check yet wether G(7) is divisible by 7. The possibilities above can easily be checked one by one. It turns out that from these numbers only G(7) = 3816547 is divisible by 7.

So we found the number, there is only one possibility and it is G = 381654729.

Lockers

A high school has a strange principal. On the first day, he has his students perform an odd opening day ceremony:

There are one thousand lockers and one thousand students in the school. The principal asks the first student to go to every locker and open it. Then he has the second student go to every second locker and close it. The third goes to every third locker and, if it is closed, he opens it, and if it is open, he closes it. The fourth student does this to every fourth locker, and so on. After the process is completed with the thousandth student, how many lockers are open?


The only lockers that remain open are perfect squares (1, 4, 9, 16, etc) because they are the only numbers divisible by an odd number of whole numbers; every factor other than the number's square root is paired up with another. Thus, these lockers will be "changed" an odd number of times, which means they will be left open. All the other numbers are divisible by an even number of factors and will consequently end up closed.

So the number of open lockers is the number of perfect squares less than or equal to one thousand. These numbers are one squared, two squared, three squared, four squared, and so on, up to thirty one squared. (Thirty two squared is greater than one thousand, and therefore out of range.) So the answer is thirty one.

Einstein's riddle

There are 5 houses in 5 different colors. In each house lives a person with a different nationality. The 5 owners drink a certain type of beverage, smoke a certain brand of cigar, and keep a certain pet. No owners have the same pet, smoke the same brand of cigar, or drink the same beverage.

Somebody owns a fish. The question is: who?

Hints:

• The Brit lives in the red house.
• The Swede keeps dogs as pets.
• The Dane drinks tea.
• The green house is on the left and next to the white house.
• The green homeowner drinks coffee.
• The person who smokes Pall Mall rears birds.
• The owner of the yellow house smokes Dunhill.
• The man living in the center house drinks milk.
• The Norwegian lives in the first house.
• The man who smokes Blends lives next to the one who keeps cats.
• The man who keeps the horse lives next to the man who smokes Dunhill.
• The owner who smokes Bluemaster drinks beer.
• The German smokes Prince.
• The Norwegian lives next to the blue house.
• The man who smokes Blends has a neighbor who drinks water

The German owns the fish

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